12t^(2/5)+19t^(1/5)+4=0

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Solution for 12t^(2/5)+19t^(1/5)+4=0 equation: 


t in (-oo:+oo)

12*t^(2/5)+19*t^(1/5)+4 = 0

t_1 = t^(1/5)

12*t_1^2+19*t_1^1+4 = 0

12*t_1^2+19*t_1+4 = 0

DELTA = 19^2-(4*4*12)

DELTA = 169

DELTA > 0

t_1 = (169^(1/2)-19)/(2*12) or t_1 = (-169^(1/2)-19)/(2*12)

t_1 = -1/4 or t_1 = -4/3

t_1 = -4/3

t^(1/5)+4/3 = 0

1*t^(1/5) = -4/3 // : 1

t^(1/5) = -4/3

( -4/3 < 0 i 1/5 in (0:1) ) => t naleu017Cy do O

t_1 = -1/4

t^(1/5)+1/4 = 0

1*t^(1/5) = -1/4 // : 1

t^(1/5) = -1/4

( -1/4 < 0 i 1/5 in (0:1) ) => t naleu017Cy do O

t belongs to the empty set

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